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Home Artificial Intelligence

Overcoming Nonsmoothness and Management Chattering in Nonconvex Optimum Management Issues

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December 30, 2025
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One would possibly encounter a lot of irritating difficulties when attempting to numerically clear up a troublesome nonlinear and nonconvex optimum management drawback. On this article I’ll contemplate such a troublesome drawback, that of discovering the shortest path between two factors by means of an impediment area for a widely known mannequin of a wheeled robotic. I’ll look at frequent points that come up when attempting to unravel such an issue numerically (specifically, nonsmoothness of the price and chattering within the management) and tips on how to deal with them. Examples assist to make clear the ideas. Get all of the code right here: https://github.com/willem-daniel-esterhuizen/car_OCP

1.1 Define

First, I’ll introduce the automobile mannequin that we’ll research all through the article. Then, I’ll state the optimum management drawback in all its element. The following part then exposes all of the numerical difficulties that come up, ending with a “wise nonlinear programme” that makes an attempt to take care of them. I’ll then current the small print of a homotopy technique, which helps in guiding the solver in direction of an excellent resolution. I’ll then present you some numerical experiments to make clear all the pieces, and end off with references for additional studying.


2. A automobile mannequin

We’ll contemplate the next equations of movement,

[
begin{align}
dot x_1(t) &= u_1(t)cos(x_3(t)),
dot x_2(t) &= u_1(t)sin(x_3(t)),
dot x_3(t) &= u_2(t),
end{align}
]

the place (t geq 0) denotes time, (x_1inmathbb{R}) and (x_2inmathbb{R}) denote the automobile’s place, (x_3inmathbb{R}) denotes its orientation, (u_1inmathbb{R}) its velocity and (u_2inmathbb{R}) its fee of turning. This can be a frequent mannequin of a differential-drive robotic, which consists of two wheels that may flip independently. This enables it to drive forwards and backwards, rotate when stationary and carry out different elaborate driving manoeuvres. Be aware that, as a result of (u_1) will be 0, the mannequin permits the automobile to cease instantaneously.

A differential drive robotic, as modelled by the equations of movement. Picture by writer.

All through the article we’ll let (mathbf{x} := (x_1, x_2, x_3)^topinmathbb{R}^3) denote the state, (mathbf{u} := (u_1, u_2)inmathbb{R}^2) denote the management, and outline (f:mathbb{R}^3timesmathbb{R}^2 rightarrow mathbb{R}^3) to be,

[
f(mathbf{x},mathbf{u}) :=
left(
begin{array}{c}
u_1cos(x_3)
u_1sin(x_3)
u_2
end{array}
right),
]

in order that we are able to succinctly write the system as,

[
dot{mathbf{x}}(t) = f(mathbf{x}(t), mathbf{u}(t)),quad tgeq 0.
]


3. Optimum path planning drawback

Contemplating the automobile mannequin within the earlier part, we wish to discover the shortest path connecting an preliminary and goal place whereas avoiding a lot of obstacles. To that finish, we’ll contemplate the next optimum management drawback:

[
newcommand{u}{mathbf{u}}
newcommand{x}{mathbf{x}}
newcommand{PC}{mathrm{PC}}
newcommand{C}{mathrm{C}}
newcommand{mbbR}{mathbb{R}}
newcommand{dee}{mathrm{d}}
newcommand{NLP}{mathrm{NLP}}
mathrm{OCP}:
begin{cases}
minlimits_{x, u} quad & J(x, u)
mathrm{subject to:}quad & dot{x}(t) = f(x(t),u(t)), quad & mathrm{a.e.},, t in[0,T], &
quad & x(0) = x^{mathrm{ini}}, & &
quad & x(T) = x^{mathrm{tar}}, & &
quad & u(t) in mathbb{U}, quad & mathrm{a.e.},, t in[0,T], &
quad & (x_1(t) – c_1^i)^2 + (x_2(t) – c_2^i)^2 geq r_i^2, quad & forall tin[0,T],, forall iin mathbb{I}, &
quad & (x, u) in C_T^3timesPC_T^2,
finish{circumstances}
]

the place (Tgeq 0) is the finite time horizon, (J:C_T^3timesPC_T^2rightarrow mbbR_{geq 0}) is the price purposeful, (x^{mathrm{ini}} inmbbR^3) is the preliminary state and (x^{mathrm{tar}}inmbbR^3) is the goal state. The management is constrained to (mathbb{U}:= [underline{u}_1, overline{u}_1]occasions [underline{u}_2, overline{u}_2]), with (underline{u}_j < 0 <overline{u}_j), (j=1,2). Round obstacles are given by a centre, ((c_1^i, c_2^i)inmbbR^2), and a radius, (r_iinmbbR_{geq 0}), with (mathbb{I}) indicating the indices of all obstacles. For the price purposeful we’ll contemplate the arc size of the curve connecting (x^{mathrm{ini}}) and (x^{mathrm{tar}}), that’s,

[
J(x,u) = int_0^Tleft(dot x_1^2(s) + dot x_2^2(s)right)^{frac{1}{2}}, dee s.
]

I’ve use the short-hand (PC_T^m) (respectively (C_T^m)) to indicate all piece-wise steady capabilities (respectively steady capabilities) mapping the interval ([0,T]) to (mbbR^m). The acronym “(mathrm{a.e.},, t in[0,T])” stands for “nearly each t in ([0,T])”, in different phrases, the spinoff might not exist at a finite variety of factors in ([0,T]), for instance, the place the management is discontinuous.

3.1 Some feedback on the OCP

The equations of movement and the presence of obstacles make the optimum management drawback nonlinear and nonconvex, which is troublesome to unravel generally. A solver might converge to regionally optimum options, which aren’t essentially globally optimum, or it might fail to discover a possible resolution although one exists.

For simplicity the obstacles are circles. These are good as a result of they’re differentiable, so we are able to use a gradient-based algorithm to unravel the OCP. (We’ll use IPOPT, which implements an interior-point technique.) The arc size perform, (J), is not differentiable when the automobile’s pace is zero. Nonetheless, as we’ll see, we are able to remove this drawback by including a small (varepsilon > 0) underneath the square-root.

Relying on the scheme used to discretise the equations of movement, there could also be chattering within the management sign. As we’ll see, this will simply be handled by penalising extreme management motion in the price perform.

The horizon size thought-about in the issue, (T), is mounted. Thus, as the issue is posed, we truly wish to discover the curve of shortest arc size for which the automobile reaches the goal in precisely (T) seconds. That is truly not a problem for our automobile as a result of it will possibly cease instantaneously and rotate on the spot. So, the options to the OCP (if the solver can discover them) would possibly encompass lengthy boring chunks initially and/or finish of the time interval if (T) may be very giant. If we wished to make the horizon size a choice variable in the issue then now we have two choices.

First, if we use a direct technique to numerically clear up the issue (as we’ll do within the subsequent part) we might range the horizon size by making the discretisation step dimension (h), which seems within the numerical integration scheme, a choice variable. It is because the dimension of the choice area have to be set on the time at which you invoke the numerical nonlinear programme solver.

The second choice is to resort to an oblique technique (in a nutshell, it’s essential clear up a boundary-value drawback that you just get from an evaluation of the issue by way of Pontryagin’s precept, usually by way of the taking pictures technique). Nonetheless, for an issue like ours, the place you’ve many state constraints, this may be fairly troublesome.


If you’re discovering this text attention-grabbing, please contemplate testing the weblog topicincontrol.com. It presents deep dives into management concept, optimization, and associated subjects, usually with freely accessible code.

4. Deriving a smart nonlinear programme

We’ll clear up the optimum management drawback utilizing direct single taking pictures. Extra exactly, we’ll take the management to be piecewise fixed over a uniform grid of time intervals and propagate the state trajectory from the preliminary situation utilizing the fourth-order Runge-Kutta (RK4) technique. We’ll then type a finite-dimensional nonlinear programme (NLP), the place the choice variables encompass the state and management at every discrete time step. This part reveals tips on how to type a “wise” NLP, which offers with the varied numerical difficulties.

4.1 The RK4 scheme

Think about the automobile’s differential equation, with preliminary situation, (x^{mathrm{ini}}), over an interval, ([0,T]),

[
dot{x}(t) = f(x(t), u(t)), quad tin[0,T], quad x(0) = x^{mathrm{ini}}.
]

Let (h>0) denote the fixed time step, and let (Okay := mathrm{flooring}(T/h)). Then the RK4 scheme reads,

[
x[k+1] = x[k] + frac{h}{6}mathrm{RK}_4(x[k], u[k]), quad forall ,, okay in[0:K-1], quad x[0] = x(0),
]

the place (mathrm{RK}_4:mbbR^3times mbbR^2 rightarrow mbbR^3) reads,

[
mathrm{RK}_4(x, u) = k_1 + 2k_2 + 2k_3 + k_4,
]

and

[
k_1 = f(x, u),quad k_2 = f(x+ frac{h}{2}k_1, u), quad k_3 = f(x + frac{h}{2}k_2, u),quad k_4 = f(x + hk_3, u).
]

The notation (x[k]) and (u[k]) is supposed to indicate the discretised state and management, respectively, in order to differentiate them from their continuous-time counterparts.

4.2 Singularity of the price purposeful

You may be tempted to contemplate the polygonal arc size as the price within the NLP, particularly,

[
sum_{k=0}^{K-1}Vertx[k+1] – x[k]Vert = sum_{okay=0}^{Okay-1}left((x_{1}[k+1] – x_1[k])^2 + (x_2[k+1] – x_2[k])^2right)^{frac{1}{2}}.
]

Nonetheless, this perform is not differentiable if for some (kin{0,1,dots,Okay-1}),

[
Vertx[k+1] – x[k]Vert = 0,
]

which regularly results in the solver failing. You would possibly see the error EXIT: Invalid quantity in NLP perform or spinoff detected when you clear up an issue with this text’s code (which makes use of IPOPT, a gradient-based solver).

One resolution is to approximate the polygonal arc size with,

[
sum_{k=0}^{K-1}left((x_{1}[k+1] – x_1[k])^2 + (x_2[k+1] – x_2[k])^2 + varepsilonright)^{frac{1}{2}},
]

with (varepsilon > 0) a small quantity. We see that, for an arbitrary (kin{1,dots,Okay-1}) and (iin{1,2}),

[
begin{align*}
frac{partial}{partial x_i[k]} &left( sum_{m=0}^{Okay-1} left(x_1[m+1] – x_1[m])^2 + (x_2[m+1] – x_2[m])^2 + varepsilonright)^{frac{1}{2}} proper) [6pt]
&= frac{x_i[k] – x_i[k-1]}{left((x_1[k] – x_1[k-1])^2 + (x_2[k] – x_2[k-1])^2 + varepsilonright)^{frac{1}{2}}}
&quad + frac{x_i[k] – x_i[k+1]}{left((x_1[k+1] – x_1[k])^2 + (x_2[k+1] – x_2[k])^2 + varepsilon proper)^{frac{1}{2}}}
finish{align*}
]

and so this perform is repeatedly differentiable, making certain easy gradients for IPOPT. (You get comparable expressions when you have a look at (frac{partial}{partial x_i[K]}) and (frac{partial}{partial x_i[0]})).

4.3 Management chattering

Management chattering is the speedy leaping/oscillation/switching of the optimum management sign. There could also be components of the answer that actually chatter (this may increasingly happen when the optimum management is bang-bang, for instance) or a numerical solver might discover a resolution that chatters artificially. Delving into this deep subject is out of this text’s scope however, very briefly, you would possibly encounter this phenomenon in issues the place the optimum resolution reveals so-called energetic arcs. These are parts of the answer alongside which the state constraints are energetic, which, in our setting, corresponds to the automobile travelling alongside the boundaries of the obstacles alongside its optimum path. When fixing issues exhibiting such arcs by way of a direct technique, as we’re doing, the numerical solver might approximate the true resolution alongside these arcs with speedy oscillation.

Fortunately, a easy technique to eliminate chattering is to only penalise management motion by including the time period:

[
deltasum_{k=0}^{K-1}Vert u[k] Vert^2
]

in the price perform, for some small (delta). (This not less than works nicely for our drawback, even for very small (delta).)

4.4 Scaling for good numerical conditioning

A well-scaled nonlinear programme is one the place small adjustments within the resolution variable lead to small adjustments in the price and the values of the constraint capabilities (the so-called constraint residuals). We will test how nicely our drawback is scaled by trying on the magnitude of the price perform, at its gradient and Hessian, as nicely the Jacobian of the constraint perform at factors within the resolution area (in particuar, on the preliminary heat begin and factors near the answer). If these portions are of comparable order then the solver shall be strong, that means it is going to normally converge in comparatively few steps. A badly-scaled drawback might take extraordinarily lengthy to converge (as a result of it’d must take very small steps of the choice variable) or just fail.

Contemplating our drawback, it is smart to scale the price by roughly the size we count on the ultimate path to be. A sensible choice is the size of the road connecting the preliminary and goal positions, name this (L). Furthermore, it then is smart to scale the constraints by (1/L^2) (as a result of we’re squaring portions right here).

4.5 The wise nonlinear programme

Taking the discussions of the earlier subsections under consideration, the wise NLP that we’ll contemplate within the numerics part reads,

[
NLP_{varepsilon, delta}:
begin{cases}
minlimits_{x, u} quad & J_{varepsilon,delta}(x, u)
mathrm{subject to:}
quad & x[k+1] = x[k] + frac{h}{6}mathrm{RK}_4(x[k], u[k]), & forall okay in[0:K-1], &
quad & x[0] = x^{mathrm{ini}}, &
quad & x[K] = x^{mathrm{tar}}, &
quad & u[k]in mathbb{U}, & forall okay in[0:K-1], &
quad & frac{1}{L^2}left( x_1[k] – c_1^i proper)^2 + frac{1}{L^2}left( x_2[k] – c_2^i proper)^2 geq frac{1}{L^2} r_i^2, quad & forall okay in[0:K], & forall iin mathbb{I},
quad & (x, u) in (mbbR^{3})^Okay occasions (mbbR^{2})^{Okay-1}, &
finish{circumstances}
]

the place (J_{varepsilon,delta}: (mbbR^{3})^Okay occasions (mbbR^{2})^{Okay-1} rightarrow mbbR_{>0}) is outlined to be,

[
J_{varepsilon,delta}(x, u) := frac{1}{L} left(sum_{k=0}^{K-1}left(Vert x[k+1] – x[k]Vert^2 + varepsilon proper)^{frac{1}{2}} + deltasum_{okay=0}^{Okay-1}Vert u[k] Vert^2 proper).
]

To help upcoming dialogue, outline the possible set, (Omega), to be the set of all pairs ((x,u)) that fulfill the constraints of (NLP_{varepsilon, delta}). A possible pair ((x^{(varepsilon,delta)}, u^{(varepsilon,delta)})) is claimed to be globally optimum offered that,

[
J_{varepsilon,delta}(x^{(varepsilon,delta)}, u^{(varepsilon,delta)}) leq J_{varepsilon,delta}(x, u),quadforall(x, u) in Omega.
]

A possible pair ((x^{(varepsilon,delta)}, u^{(varepsilon,delta)})) is claimed to be regionally optimum offered that there exists a sufficiently small (gamma >0) for which,

[
J_{varepsilon,delta}(x^{(varepsilon,delta)}, u^{(varepsilon,delta)}) leq J_{varepsilon,delta}(x, u),quadforall(x, u) in Omegacap mathbf{B}_{gamma}(x^{(varepsilon,delta)}, u^{(varepsilon,delta)}).
]

Right here (mathbf{B}_{gamma}(x^{(varepsilon,delta)}, u^{(varepsilon,delta)}) ) denotes a Euclidean ball of radius (gamma>0) centred concerning the level ((x^{(varepsilon,delta)}, u^{(varepsilon,delta)}) ).


5. A homotopy technique

Recall that the issue is nonlinear and nonconvex. Thus, if we had been to only select a small (varepsilon>0) and (delta>0) and throw (NLP_{varepsilon, delta}) at a solver, then it might fail although possible pairs would possibly exist, or it might discover “dangerous” regionally optimum pairs. One method to take care of these points is to information the solver in direction of an answer by successively fixing simpler issues that converge to the troublesome drawback.

That is the concept behind utilizing a homotopy technique. We’ll information the solver in direction of an answer with a easy algorithm that successively offers the solver an excellent heat begin:

Homotopy algorithm

[
begin{aligned}
&textbf{Input:}text{ Initial parameters } varepsilon_{mathrm{ini}}>0, delta_{mathrm{ini}}>0. text{ Tolerances } mathrm{tol}_{varepsilon}>0, mathrm{tol}_{delta}>0.
&textbf{Output:} text{ Solution } (x^{(mathrm{tol}_{varepsilon}, mathrm{tol}_{delta})}, u^{(mathrm{tol}_{varepsilon}, mathrm{tol}_{delta})}) text{ (if it can find one)}
&quad text{Get initial warm start}, (x^{mathrm{warm}}, u^{mathrm{warm}}) text{ (not necessarily feasible)}
&quad i gets 0
&quad textbf{ While } varepsilon > mathrm{tol}_{varepsilon} text{ and } delta > mathrm{tol}_{delta}:
&quadquad varepsilongets max { varepsilon_{mathrm{ini}} / 2^i, mathrm{tol}_{varepsilon} }
&quadquad deltagets max { delta_{mathrm{ini}} / 2^i, mathrm{tol}_{delta} }
& quadquad text{ Solve } NLP_{varepsilon, delta} text{ with warm start } (x^{mathrm{warm}}, u^{mathrm{warm}})
& quadquad text{Label the solution } (x^{(varepsilon, delta)}, u^{(varepsilon, delta)}).
&quadquad (x^{mathrm{warm}}, u^{mathrm{warm}})gets (x^{(varepsilon, delta)}, u^{(varepsilon, delta)}).
&quadquad igets i + 1
&textbf{end while}
&textbf{return}, (x^{(mathrm{tol}_{varepsilon}, mathrm{tol}_{delta})}, u^{(mathrm{tol}_{varepsilon}, mathrm{tol}_{delta})})
end{aligned}
]

NOTE!: The homotopy algorithm is supposed to assist the solver discover a good resolution. Nonetheless, there’s no assure that it’ll efficiently discover even a possible resolution, nevermind a globally optimum one. For some concept concerning so-called globallly convergent homotopies you’ll be able to seek the advice of the papers, [1] and [2].


6. Numerical experiments

On this part we’ll contemplate (NLP_{varepsilon, delta}) with preliminary and goal states (x^{mathrm{ini}} = (2,0,frac{pi}{2})) and (x^{mathrm{tar}} = (-2,0,mathrm{free})), respectively (thus (L = 4)). We’ll take the horizon as (T=10) and hold the discretisation step dimension within the RK4 scheme fixed at (h=0.1), thus (Okay=100). Because the management constraints we’ll take (mathbb{U} = [-1,1] occasions [-1, 1]), and we’ll contemplate this attention-grabbing impediment area:

6.1 Checking conditioning

First, we’ll test the issue’s scaling on the heat begin. Stack the state and management into a protracted vector, (mathbf{d}inmbbR^{3K + 2(Okay-1)}), as follows:

[
mathbf{d} := (x_1[0],x_2[0],x_3[0],x_1[1],x_2[1],x_3[1],dots,u_1[0],u_2[0],u_1[1],u_2[1],dots,u_1[K-1],u_2[K-1]),
]

and write (NLP_{varepsilon, delta}) as:

[
newcommand{d}{mathbf{d}}
newcommand{dini}{mathbf{d}^{mathrm{ini}}}
begin{cases}
minlimits_{mathbf{d}} quad & J_{varepsilon,delta}(d)
mathrm{subject to:}
quad & g(d) leq mathbf{0},
end{cases}
]

the place (g) collects all of the constraints. As a heat begin, name this vector (dini), we’ll take the road connecting the preliminary and goal positions, with (u_1[k] equiv 0.1) and (u_2[k] equiv 0).

We must always take a look on the magnitudes of the next portions on the level (dini):

  • The fee perform, (J_{varepsilon,delta}(dini))
  • Its gradient, (nabla J_{varepsilon,delta}(dini))
  • Its Hessian, (mathbf{H}(J_{varepsilon,delta}(dini)))
  • The constraint residual, (g(dini))
  • Its Jacobian, (mathbf{J}(g(dini)))

We will do that with the code from the repo:

import numpy as np
from car_OCP import get_initial_warm_start, build_and_check_scaling

x_init = np.array([[2],[0],[np.pi/2]])
x_target = np.array([[-2],[0]])

T = 10 # Horizon size
h = 0.1 # RK4 time step

obstacles = [
    {'centre': (0,0), 'radius': 0.5},
    {'centre': (-0.5,-0.5), 'radius': 0.2},
    {'centre': (1,0.5), 'radius': 0.3},
    {'centre': (1,-0.35), 'radius': 0.3},
    {'centre': (-1.5,-0.2), 'radius': 0.2},
    {'centre': (1.5,-0.2), 'radius': 0.2},
    {'centre': (-0.75,0), 'radius': 0.2},
    {'centre': (-1.25,0.2), 'radius': 0.2}
]

constraints = {
    'u1_min' : -1,
    'u1_max' : 1,
    'u2_min' : -1,
    'u2_max' : 1,
}

warm_start = get_initial_warm_start(x_init, x_target, T, h)

build_and_check_scaling(x_init, x_target, obstacles, constraints, T, h, warm_start, eps=1e-4, delta=1e-4)

=== SCALING DIAGNOSTICS ===

Goal J : 1.031e+00

||∇J||_2 : 3.430e-01

||Hess J||_Frob : 1.485e+02

||g||_2 : 7.367e+00

||Jac g||_Frob : 2.896e+01

============================

With small (varepsilon) and (delta), and with our chosen (dini), the target ought to clearly be near 1. The dimensions of its gradient and of the constraint residuals on the heat begin ought to be of comparable order. Within the print-out, (Vert nabla J Vert_2) denotes the Euclidean norm. The fee perform’s Hessian will be of bigger order (this will increase with a finer time step). Within the print-out, (Vert nabla mathrm{Hess} J Vert_{mathrm{Frob}}) is the Frobenius norm of the Hessian matrix, which, intuitively talking, tells you “how huge” the linear transformation is “on common”, so it’s an excellent measure to contemplate. The Jacobian of (g) can be of barely bigger order.

The print-out reveals that our drawback is well-scaled, nice. However one final thing we’ll additionally do is inform IPOPT to scale the issue earlier than we clear up it, with "ipopt.nlp_scaling_method":

.... arrange drawback ....

opts = {"ipopt.print_level": 0, 
        "print_time": 0, 
        "ipopt.sb": "sure",
        "ipopt.nlp_scaling_method": "gradient-based"}

opti.reduce(price)
opti.solver("ipopt", opts)

6.2 Fixing WITHOUT homotopy

This subsection reveals the impact of the parameters (varepsilon) and (delta) on the answer, with out working the homotopy algorithm. In different phrases, we repair (varepsilon) and (delta), and clear up (NLP_{varepsilon, delta}) straight, with out even specifying an excellent preliminary guess. Right here is an instance of how you should use the article’s repo to unravel an issue:

import numpy as np
from car_OCP import solve_OCP, get_arc_length, plot_solution_in_statespace_and_control

eps=1e-2
delta=1e-2

x_init = np.array([[2],[0],[np.pi/2]])
x_target = np.array([[-2],[0]])

T = 10 # Horizon size
h = 0.1 # RK4 time step

obstacles = [
    {'centre': (0,0), 'radius': 0.5},
    {'centre': (-0.5,-0.5), 'radius': 0.2},
    {'centre': (1,0.5), 'radius': 0.3},
    {'centre': (1,-0.35), 'radius': 0.3},
    {'centre': (-1.5,-0.2), 'radius': 0.2},
    {'centre': (1.5,-0.2), 'radius': 0.2},
    {'centre': (-0.75,0), 'radius': 0.2},
    {'centre': (-1.25,0.2), 'radius': 0.2}
]

constraints = {
    'u1_min' : -1,
    'u1_max' : 1,
    'u2_min' : -1,
    'u2_max' : 1,
}

x_opt, u_opt = solve_OCP(x_init, x_target, obstacles, constraints, T, h, warm_start=None, eps=eps, delta=delta)

plot_solution_in_statespace_and_control(x_opt, u_opt, obstacles, arc_length=np.spherical(get_arc_length(x_opt), 2), obstacles_only=False, eps=eps, delta=delta)

Be aware how the solver would possibly discover regionally optimum options which might be clearly not so good, like within the case (varepsilon) = (delta) = 1e-4. That is one motivation for utilizing homotopy: you possibly can information the solver to a greater regionally optimum resolution. Be aware how (delta) impacts the chattering, with it being actually dangerous when (delta=0). The solver simply fails when (varepsilon=0).

The answer with eps = delta = 1e-2. Picture by Creator.
The answer with eps = delta = 1e-4. Be aware how the answer is regionally optimum, and never so good. Picture by writer.
Resolution with eps = 1e-6, and delta = 0. Be aware how dangerous the management chattering is. Picture by writer.

6.3 Fixing WITH homotopy

Let’s now clear up the issue with the homotopy algorithm. I.e., we iterate over (i) and feed the solver the earlier drawback’s resolution as a heat begin on every iteration. The preliminary guess we offer (at (i=0)) is similar one we used once we checked the conditioning, that’s, it’s simply the road connecting the preliminary and goal positions, with (u_1[k] equiv 0.1) and (u_2[k] equiv 0).

The figures beneath present the answer obtained at varied steps of the iteration within the homotopy algorithm. The parameter (delta) is saved above 1e-4, so we don’t have chattering.

Resolution by way of homotopy, at eps = delta = 1e-4. Picture by writer.
Resolution by way of homotopy, at eps = 1e-5, delta = 1e-4. Picture by writer.
Resolution by way of homotopy, at eps = 1e-6, delta = 1e-4. Picture by writer.

As one would count on, the arc size of the answer obtained by way of the homotopy algorithm monotonically decreases with growing (i). Right here, (delta)=1e-4 all through.


7. Conclusion

I’ve thought-about a troublesome optimum management drawback and gone by means of the steps one must observe to unravel it intimately. I’ve proven how one can virtually take care of problems with nondifferentiability and management chattering, and the way a easy homotopy technique can result in options of higher high quality.


8. Additional studying

A traditional e-book on sensible points surrounding optimum management is [3]. Seek the advice of the papers [4] and [5] for well-cited surveys of numerical strategies in optimum management. The e-book [6] is one other glorious reference on numerical strategies.


References

[1] Watson, Layne T. 2001. “Idea of Globally Convergent Chance-One Homotopies for Nonlinear Programming.” SIAM Journal on Optimization 11 (3): 761–80. https://doi.org/10.1137/S105262349936121X.

[2] Esterhuizen, Willem, Kathrin Flaßkamp, Matthias Hoffmann, and Karl Worthmann. 2025. “Globally Convergent Homotopies for Discrete-Time Optimum Management.” SIAM Journal on Management and Optimization 63 (4): 2686–2711. https://doi.org/10.1137/23M1579224.

[3] Bryson, Arthur Earl, and Yu-Chi Ho. 1975. Utilized Optimum Management: Optimization, Estimation and Management. Taylor; Francis.

[4] Betts, John T. 1998. “Survey of Numerical Strategies for Trajectory Optimization.” Journal of Steering, Management, and Dynamics 21 (2): 193–207.

[5] Rao, Anil V. 2009. “A Survey of Numerical Strategies for Optimum Management.” Advances within the Astronautical Sciences 135 (1): 497–528.

[6] Gerdts, Matthias. 2023. Optimum Management of ODEs and DAEs. Walter de Gruyter GmbH & Co KG.

Tags: ChatteringControlNonconvexNonsmoothnessOptimalOvercomingProblems

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